A drives straight off the edge of a cliff that is 54m high.the police at the scene of the accident obseve that the point of impact 130m from the base of the cliff.How fast was the car traveling when it went over the cliff?

Answer 1

How long to fall 54 meters with no initial vertical velocity?
h = (1/2) g t^2

54 = 4.9 t^2
t = sqrt (54/4.9)

then
130 = u t
so
u = 130/t