Asked by Henry

The first and the last terms of an Arithmetic Progression are 6 and 171 in that order. If there are 14 terms, find the 16th term of the Arithmetic Progression.
Answered by Reiny
given:
a = 6
a + 13d = 171
6+13d = 171
13d = 165
d = 165/13

term16 = term14 + 2d
= 171 + 330/16 = 2553/13

term 16 = a + 15d
= 6 + 15(165/13) = 2553/13
Answered by Nancy
Not correct
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