Asked by Wesley
X is a point 2800 m East of Y. Due North of X is another point Z whose bearing from Y is N63°E. P is due North of Y and its bearing from X is N25°W. Calculate XZ and XP (give your answers to four significant figures)?
Answers
Answered by
Steve
Just draw a diagram. All those right angles help a lot.
XZ/2800 = tan(90-63)°
2800/XP = cos(90-25)°
XZ/2800 = tan(90-63)°
2800/XP = cos(90-25)°
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