Question

You want to neutralize 6 mol of sulfuric acid with 6.0 M sodium hydroxide. How much 6.0 M sodium hydroxide must you add to react exactly with the sulfuric acid?
2NaOH(aq)+H2SO4(aq)-->2H2O(l)+Na2SO4(aq)
2 moles sodium hydroxide for every 1 mol sulfuric acid.
I do not know what steps to take to solve this problem from here.
PLEASE HELP

Answer 1

You did the most important first two. The next one is the easy one.

So you want to neutralize 6 mols H2SO4, that will take 12 mols NaOH as you correctly stated.
Then M NaOH = mols NaOH/L NaOH. You know mols NaOH and M NaOH, solve for L NaOH. Convert to mL if needed.