Asked by Veronica
Rewrite: tan(cos^−1 (v)) as an algebraic expression in v.
Please help me understand.
Please help me understand.
Answers
Answered by
Damon
cos theta = adjacent/hypotenuse
call adjacent side v
call hypotenuse 1
then cos theta = v
opposite side = sqrt(1^2 - v^2)
tan theta = sqrt(1-v^2) /v
call adjacent side v
call hypotenuse 1
then cos theta = v
opposite side = sqrt(1^2 - v^2)
tan theta = sqrt(1-v^2) /v
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