Asked by Rosi3
Tom exerts a force of 75N horizontally to a skateboarder, Steven's mass is 65kg, for a distance of 2.0m on a frictionless floor. A)How much work did Tom do on Steve? B) What was Steven's final speed?
Answers
Answered by
Henry
A. Work = F*d = 75 * 2 = 150 J.
B. Work also = Change in kinetic energy = 0.5M*V^2 = 150, M = 65 kg, V = ?.
B. Work also = Change in kinetic energy = 0.5M*V^2 = 150, M = 65 kg, V = ?.
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