Asked by patricia
6. In a GP the 3rd term is equal to four times the first term and the sixth term is equal to three times the fourth term plus 32. Determine the sequence.
Answers
Answered by
Reiny
GP
ar^2 = 4a ----> r^2 = 4
r = ±2
ar^5 = 3ar^3 + 32
if r = +2
32a = 24a + 32
8a =32
a = 4
the sequence is 4,8,16,32,64, 128, ...
if r = -2
-32a = -24a + 32
-8a = 32
a = -4
the sequence is -4, 8, -16, 32, -64, 128, ...
ar^2 = 4a ----> r^2 = 4
r = ±2
ar^5 = 3ar^3 + 32
if r = +2
32a = 24a + 32
8a =32
a = 4
the sequence is 4,8,16,32,64, 128, ...
if r = -2
-32a = -24a + 32
-8a = 32
a = -4
the sequence is -4, 8, -16, 32, -64, 128, ...
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