Asked by Marie

My teacher assigned us this problem:
Using the following logarithms
Log2,log3 and log10 solve for the log150,log 75 incorporating the properties of logarithms ,i tried ,but failed plz help!!

Answers

Answered by Maya
Well, with log150 it's log3+log(10)^2-log2
With log75 it is equivalent to log3+log(10)^2-log(2)^2
Hope this helped
Answered by Steve
not quite. log(x^2) = 2logx

150 = 3*100/2, so
log 150 = log3 + 2log10 - log2

75 = 3*(10/2)^2, so
log75 = log3 + 2log10 - 2log2
or, since 75 = 150/2
log75 = log150-log2 as above
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