Question

what is the least perimeter of a rectangle with an area of 32 square feet

Answer 1

P = 2L + 2W

The dimensions could be
1 by 32
2 by 16
4 by 8

Answer 2

The least perimeter is obtained when you have a square
let the side be s
s^2 = 32
s = √32 = 4√2

so the least perimeter is 8√2

by Calculus:
let the width be x
then the length is 32/x

P = 2x + 2y = 2x + 64/x
P' = 2 - 64/x^2 = 0 for a min of P

2 = 64/x^2
x^2 = 32
x = √32
etc (as above)

Answer 3

Oh ye

Answer 4

Oh yea

Answer 5

The dimensions 1 by 32,2 by 16, and 4 by 8 and if you calculate the perimeters here are the results:24,66 and 36. And as you can see the least is the rectangle with the dimension of 4 by 8 and the perimeter of 24.

Answer 6

oh yeahhhhh

Answer 7

The area of the shaded rectangle shown below is 15 ft.² what is the perimeter of the figure

Answer 8

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