Consider the reaction: 2H2+2NO - N2+2H2O. Initially 1.20mol of H2 and 0.95mol of NO are placed in a 2.50L container(all reactants and products are gases) if after 5seconds the amount of H2 has been reduced to 1.02mol.

Question

Consider the reaction: 2H2+2NO -> N2+2H2O. Initially 1.20mol of H2 and 0.95mol of NO are placed in a 2.50L container(all reactants and products are gases) if after 5seconds the amount of H2 has been reduced to 1.02mol.
How much NO is left? And how much N2 and H2O has been prodeced?

DrBob222 · Answer

......2H2 + 2NO -> N2 + 2H2O I.....1.2..0.95....0......0 C.....-2x...-2x....x.....2x 5sec..1.02.0.95-2x..x....2x So 1.20-2x = 1.02 Solve for x and evaluate the other values you want to calculate.