14.Calculate the quantity of heat required to raise the temperature of 10g of ice

Question

from −10°C to steam 110°C and draw the graph of Temperature (°c) versus
Heat (Joule or Cal.)

Answer 1

To calculate the quantity of heat required, we need to consider the different phases of water and the specific heat capacities associated with each phase.

1. Heating ice from -10°C to 0°C:
Q = m * c * ΔT
Q = 10g * 2.09 J/g°C * 10°C
Q = 209 J

2. Melting ice at 0°C:
Q = m * Lf
Q = 10g * 334 J/g
Q = 3340 J

3. Heating water from 0°C to 100°C:
Q = m * c * ΔT
Q = 10g * 4.18 J/g°C * 100°C
Q = 4180 J

4. Vaporizing water at 100°C:
Q = m * Lv
Q = 10g * 2260 J/g
Q = 22600 J

5. Heating steam from 100°C to 110°C:
Q = m * c * ΔT
Q = 10g * 2.01 J/g°C * 10°C
Q = 201 J

Total heat required = 209 J + 3340 J + 4180 J + 22600 J + 201 J
= 30230 J

Now, let's draw the graph of Temperature (°c) versus Heat (Joule or Cal.):

Temperature (°C) Heat (Joules)
-10 0
0 209
0 3549
100 7729
100 30329
110 30530

The graph will show a linear increase in heat as the temperature of the ice increases, with significant increases at the phase changes from solid to liquid and liquid to gas.