14. A 0.135 kg ball is tossed upward from a height of 1.20 m above the ground with an initial speed of 15.0 m/s . What is the ball’s total mechanical energy at the moment it is tossed upward?(1 point)

1 answer

To find the total mechanical energy of the ball at the moment it is tossed upward, we need to calculate both its kinetic energy (KE) and its gravitational potential energy (PE).

  1. Calculate the Kinetic Energy (KE): The formula for kinetic energy is:

\[ KE = \frac{1}{2}mv^2 \]

where:

  • \( m \) is the mass of the ball (0.135 kg),
  • \( v \) is the initial speed of the ball (15.0 m/s).

Substituting the values:

\[ KE = \frac{1}{2} \times 0.135 , \text{kg} \times (15.0 , \text{m/s})^2 \] \[ KE = \frac{1}{2} \times 0.135 \times 225 \] \[ KE = \frac{1}{2} \times 30.375 \] \[ KE = 15.1875 , \text{J} \]

  1. Calculate the Gravitational Potential Energy (PE): The formula for gravitational potential energy is:

\[ PE = mgh \]

where:

  • \( h \) is the height above the ground (1.20 m),
  • \( g \) is the acceleration due to gravity (approximately \( 9.81 , \text{m/s}^2 \)).

Substituting the values:

\[ PE = 0.135 , \text{kg} \times 9.81 , \text{m/s}^2 \times 1.20 , \text{m} \] \[ PE = 0.135 \times 11.772 \] \[ PE \approx 1.588 , \text{J} \]

  1. Total Mechanical Energy (E): The total mechanical energy is the sum of kinetic and potential energy:

\[ E = KE + PE \]

Substituting the values we calculated:

\[ E = 15.1875 , \text{J} + 1.588 , \text{J} \] \[ E \approx 16.7755 , \text{J} \]

Therefore, the ball’s total mechanical energy at the moment it is tossed upward is approximately 16.78 J.