(14^3 • 27^-7)^0/3^4

1 answer

To simplify the expression \((14^3 \cdot 27^{-7})^0 / 3^4\), we first observe that anything raised to the power of 0 is 1 (as long as the base is not zero). Therefore, we have:

\[ (14^3 \cdot 27^{-7})^0 = 1 \]

Now substituting this into the expression, we get:

\[ \frac{1}{3^4} \]

Next, we calculate \(3^4\):

\[ 3^4 = 81 \]

So, the expression simplifies to:

\[ \frac{1}{81} \]

Thus, the final simplified result is:

\[ \frac{1}{81} \]