Asked by Anonymous
A certain vehicle loses 35% of its value each year.
Compute the value of the vehicle at the end of the 3rd year if the car has an initial value of $25,000
Compute the value of the vehicle at the end of the 3rd year if the car has an initial value of $25,000
Answers
Answered by
Anonymous
1,250
A trick I've learned is by removing 10% each time, and that's easy because all you have to do is move the number over once to the right.
25,000 -> 2,500
2,500 * 3 = 7,500
10% of 25,000 is 2,500 / 2 = 1,250 Or 5% of 25,000
7,500 + 1,250 = 8,750
8750 x 3 = 26,250
26,250 - 25,000 = 1,250
A trick I've learned is by removing 10% each time, and that's easy because all you have to do is move the number over once to the right.
25,000 -> 2,500
2,500 * 3 = 7,500
10% of 25,000 is 2,500 / 2 = 1,250 Or 5% of 25,000
7,500 + 1,250 = 8,750
8750 x 3 = 26,250
26,250 - 25,000 = 1,250
Answered by
Reiny
huhh???
value at end of year 1 = 25000(.65) = 16250
value at end of year 2 = 16250(.65) = 10562.50
value at end of year 3 = 10562.50(.65) = 6865.63
or in 1 step
value = 25000(.65)^3 = 6865.63
So much for you little trick, it is blatantly wrong.
value at end of year 1 = 25000(.65) = 16250
value at end of year 2 = 16250(.65) = 10562.50
value at end of year 3 = 10562.50(.65) = 6865.63
or in 1 step
value = 25000(.65)^3 = 6865.63
So much for you little trick, it is blatantly wrong.
Answered by
Anonymous
How did you get 16,250? You probably need to recheck your answers.
Answered by
Anonymous
Wait, just realized my mistake. It's actually 18,134 is the total loss of the value of the car. 25,000 - 18,134 = 6,866 (The car's value now)
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