Asked by madhu
force has the dependence Fx = -ax4 on the position x, with the constant a = 25.0 N/m4. The work performed by this force when the position of its point of application changes from 0.75 m to 1.25 m is
Answers
Answered by
Damon
Fx = -a x^4 I assume you mean
F= -25 x^4
dW = F dx = -25 x^4 dx
W = -(25/5)x^5 at x = 1.25-at.75
W = -5 (1.25^5 - .75^5)
F= -25 x^4
dW = F dx = -25 x^4 dx
W = -(25/5)x^5 at x = 1.25-at.75
W = -5 (1.25^5 - .75^5)
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