Asked by Anonymous
For which k will the graph of f(x)=x^2−kx+k^2 cross the x-axis twice?
Answers
Answered by
Reiny
let's rephrase the question.
For what values of k will the quadratic
x^2 - kx + k^2 = 0 have 2 solutions
when b^2 - 4ac > 0
k^2 - 4(1)(k^2) >0
-3k^2 > 0
k^2 < 0
any number squared is always positive, so there is no value of k for which the graph will cross the x-axis twice
you can test this here
http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E2+-+5x+%2B+25
in my example I let k = 5
you can change the equation by editing the value of k, and the graph will always be above the x-axis
For what values of k will the quadratic
x^2 - kx + k^2 = 0 have 2 solutions
when b^2 - 4ac > 0
k^2 - 4(1)(k^2) >0
-3k^2 > 0
k^2 < 0
any number squared is always positive, so there is no value of k for which the graph will cross the x-axis twice
you can test this here
http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E2+-+5x+%2B+25
in my example I let k = 5
you can change the equation by editing the value of k, and the graph will always be above the x-axis
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.