Asked by Need Help
The question is to evaluate each logarithm:
My professor wants us to show work. Could you please tell me if I'm on the right track? Thank you!!!
1. log6^(1/36)= -2
2. ln(1/e^4)= 1/e^2
3. log7^1= 0
4. log4^64= ln64/ln4= 3
5. log10^8= ln8/ln10= .9031
6. log3^(radical 3)= I wasn't sure how to show the work on this one. I plugged it into my calculator and got .8263
My professor wants us to show work. Could you please tell me if I'm on the right track? Thank you!!!
1. log6^(1/36)= -2
2. ln(1/e^4)= 1/e^2
3. log7^1= 0
4. log4^64= ln64/ln4= 3
5. log10^8= ln8/ln10= .9031
6. log3^(radical 3)= I wasn't sure how to show the work on this one. I plugged it into my calculator and got .8263
Answers
Answered by
Reiny
#1
How did you get -2 ??
log 6^(1/36)
= (1/36) log 6 = appr .0216
#2
ln(1/e^4)
= ln1 - ln e^4
= 0 - 4lne
= 0 - 4(1) = -4
#3
log 7^1
= log 7 = appr .845
#4
log 4^64
= 64 log4 = appr 38.532
#5
log 10^8
= 8log10
= 8
#6 --- the only one you got right
How did you get -2 ??
log 6^(1/36)
= (1/36) log 6 = appr .0216
#2
ln(1/e^4)
= ln1 - ln e^4
= 0 - 4lne
= 0 - 4(1) = -4
#3
log 7^1
= log 7 = appr .845
#4
log 4^64
= 64 log4 = appr 38.532
#5
log 10^8
= 8log10
= 8
#6 --- the only one you got right
Answered by
Steve
Some of these blokes use
log6^(1/36) to mean log<sub>6</sub>(1/36), which is indeed -2
#2 ln(1/e^4) = ln(e^-4) = -4
#3 ok
#4 ok
#5 since the other logs specify a base, this must be just a common log, and log 10^8 = 8
#6 log<sub>3</sub>√3 = log<sub>3</sub>3^(1/2) = 1/2
log6^(1/36) to mean log<sub>6</sub>(1/36), which is indeed -2
#2 ln(1/e^4) = ln(e^-4) = -4
#3 ok
#4 ok
#5 since the other logs specify a base, this must be just a common log, and log 10^8 = 8
#6 log<sub>3</sub>√3 = log<sub>3</sub>3^(1/2) = 1/2
Answered by
Need Help
Hi thank you so much for helping me. Yeah, I am sorry. I do not know how to make the base numbers small like that. Thank you both again for the help!
Answered by
Reiny
Thanks Steve
Had an inkling that's what he was doing, but then it was contradicted in how he worked the last one.
btw, was it overkill in my solution to
http://www.jiskha.com/display.cgi?id=1461944692
Almost gave up on it, but found some clues on a webpage.
Had an inkling that's what he was doing, but then it was contradicted in how he worked the last one.
btw, was it overkill in my solution to
http://www.jiskha.com/display.cgi?id=1461944692
Almost gave up on it, but found some clues on a webpage.
Answered by
Steve
The subscripts are a trick of HTML. Most of the codes do not work on this site, but the sub and /sub tags work.
For superscripts, the sup and /sup tags work.
enclose the words in <> brackets to make them into HTML tags.
For superscripts, the sup and /sup tags work.
enclose the words in <> brackets to make them into HTML tags.
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