Asked by John
You sell lemonade for $2 and orange juice for $3. You sell 100 cups for $240. How many cups of lemonade and how many cups of orange juice were sold
Answers
Answered by
Anonymous
Let total no. of lemonade and orange juice cups sold be x and y respectively.
x+y=100
2x+3y=240
Solve for x and y :)
x+y=100
2x+3y=240
Solve for x and y :)
Answered by
Jasmine
L + O = 100 or L = 100 - O
2L + 3O = 240
substitute first equation into second equation:
2(100 - O) + 3O = 240
200 - 2O + 3O = 240
O = 40 cups
using first equation:
L = 100 - 40 = 60 cups
check using second equation:
2(60) + 3(40) = 240
120 + 120 = 240 checks
Sold 40 cups of orange juice and 60 cups of lemonade.
2L + 3O = 240
substitute first equation into second equation:
2(100 - O) + 3O = 240
200 - 2O + 3O = 240
O = 40 cups
using first equation:
L = 100 - 40 = 60 cups
check using second equation:
2(60) + 3(40) = 240
120 + 120 = 240 checks
Sold 40 cups of orange juice and 60 cups of lemonade.
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