During the month of June, Ava kept track of the number of days she saw birds in her garden. She saw birds on 18 days of the month. What experimental probability that she will see birds in her garden on July 1?
Can somebody show me how to work this problem out?
4 answers
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
0.6
1 answer