Asked by Santanu
How much shorter is to walk diagonally across a rectangular field that is 24cm long and 18cm width than along two of its adjacent sides.
Answers
Answered by
Chloe
Walking along two of its adjacent sides: 24 + 18 = 42cm
Draw the diagonal (to form two triangles). Find the hypotenuse of one of the triangles to find the diagonal. Use pythagoras theorem:
c = sqrt[a^2 + b^2]
= sqrt[24^2 + 18^2]
= 30cm
Therefore, it is 12cm shorter to walk diagonally across.
Draw the diagonal (to form two triangles). Find the hypotenuse of one of the triangles to find the diagonal. Use pythagoras theorem:
c = sqrt[a^2 + b^2]
= sqrt[24^2 + 18^2]
= 30cm
Therefore, it is 12cm shorter to walk diagonally across.
Answered by
Anonymous
Thanks for the answer
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