Asked by IDK

A container of gas is at a pressure of 1.3x10^5 Pa and a volume of 6.0m^3. How much work is done by the gas if it expands at constant pressure to twice its initial volume? Please help ;_;
Answered by ik
W = P(V2 - V1)
W = 1.3x10^5 (2x6 - 6 )
W = 780000 J
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