Question
the sum of 2 numbers is 83. three times the smaller number is subtracted from the larger number is 19.
how do i set this problem up?
how do i set this problem up?
Answers
larger x
smaller y
x+y = 83
x - 3y = 19
subtract them:
4y = 64
y = 16 , then
x = 67
larger is 67, the smaller is 16
smaller y
x+y = 83
x - 3y = 19
subtract them:
4y = 64
y = 16 , then
x = 67
larger is 67, the smaller is 16
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