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An unkown vol of 2Mol of NaOH reacted with 3g of ethanoic acid .....get the volume of NaOH
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A food scientist also tested some ethanoic acid solution. Ethanoic acid is the acid which is found in vinegar.His results are
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Find the Molecular weight of unknown acid #5...
Mass of acid #5 = 1.200g Volume (acid was mixed in) = 100ml (distilled water)
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Vinegar contain ethanoic acid.titration of 3.00g of vinegar with 0.12mol NaOH solution requires 23.0cm to reach the equivalence
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1. Suppose that 10.2 mL of 0.0512 M NaOH were required to titrate a sample of unkown acid. How many moles of NaOH were used?
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