Question

When irradiated with a radiation of wavelength 58.4 nm the electron of H atom was ejected

with kinetic energy 7.6 eV. Calculate the ionization energy.
bobpursley
convert the photon wavelenght to energy, in ev.
subtract the 7.5eV, and you have it.

E=PlancksConstant*speedlight/lambda
h=4.15)×10−15 eV s

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