Asked by kamila t arakkal
When irradiated with a radiation of wavelength 58.4 nm the electron of H atom was ejected
with kinetic energy 7.6 eV. Calculate the ionization energy.
with kinetic energy 7.6 eV. Calculate the ionization energy.
Answers
Answered by
bobpursley
convert the photon wavelenght to energy, in ev.
subtract the 7.5eV, and you have it.
E=PlancksConstant*speedlight/lambda
h=4.15)×10−15 eV s
subtract the 7.5eV, and you have it.
E=PlancksConstant*speedlight/lambda
h=4.15)×10−15 eV s
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