Asked by kamila t arakkal

When irradiated with a radiation of wavelength 58.4 nm the electron of H atom was ejected

with kinetic energy 7.6 eV. Calculate the ionization energy.

Answers

Answered by bobpursley
convert the photon wavelenght to energy, in ev.
subtract the 7.5eV, and you have it.

E=PlancksConstant*speedlight/lambda
h=4.15)×10−15 eV s
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