Use t and substitute into
the equation.
D = 5 + 5(0) = 5
D = 5 +5(1) = 10
etc.
The table Below using the following equation . D= 5 + 5t which set of numbers can be the value of D
t . D
0 .
1 .
2 .
3 .
A) 0,5,10,15
B) 5,10,15,20
C) 0,10,15,20
D) 0,6,12,18
1 answer
1 answer