Asked by Anonymous
A man is 2 m tall is walking at a rate of 1 m per second in a straight line away from a 10 m lamppost. How fast is the tip of his shadow moving away from the lamppost?
Answers
Answered by
Steve
If his distance from the pole is x and the length of the shadow is s, then
s/2 = (s+x)/10
1/2 ds/dt = 1/10 (ds/dt + dx/dt)
4 ds/dt = dx/dt
So, the length of the shadow is growing 1/4 as fast as the man's speed.
But that's not how fast the tip of the shadow is moving. You can figure that out, I think.
s/2 = (s+x)/10
1/2 ds/dt = 1/10 (ds/dt + dx/dt)
4 ds/dt = dx/dt
So, the length of the shadow is growing 1/4 as fast as the man's speed.
But that's not how fast the tip of the shadow is moving. You can figure that out, I think.
Answered by
ChrismB
i am not getting the point,can you elaborate more
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