Asked by Heaven
Sketch the graph of this quadratic function: f(x)= 3(x-2)^2 -10. Be sure to explain the steps you take.
**I don't need help with the graph part but I need to find the x and y intercepts, the equation of the axis of symmetry and the coordinates of the vertex from the function above. If someone could please provide help, that would be great. Thanks in advance.
**I don't need help with the graph part but I need to find the x and y intercepts, the equation of the axis of symmetry and the coordinates of the vertex from the function above. If someone could please provide help, that would be great. Thanks in advance.
Answers
Answered by
Steve
f(x) = 3x^2 - 12x + 2
the y-intercept is clearly at 2.
x-intercepts? where y=0. Use the quadratic formula to get
x = 2±√(10/3)
the y-intercept is clearly at 2.
x-intercepts? where y=0. Use the quadratic formula to get
x = 2±√(10/3)
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