Question
the power (P) generated in a electrical circuit is proportional to the square of the current ( L amps) . when the power is 108, the current is 6 amps.
a_ write down the relationship between P,L and the constant of variation k .
b_ calculate the value of k
c_ calculate the value of L when p= 75 watts
a_ write down the relationship between P,L and the constant of variation k .
b_ calculate the value of k
c_ calculate the value of L when p= 75 watts
Answers
Reiny
P = k L^2
when P=108, L=6
108 = 36K
k = 3
P = 3L^2
75 = 3L^2
L^2 = 25
L = 5
when P=108, L=6
108 = 36K
k = 3
P = 3L^2
75 = 3L^2
L^2 = 25
L = 5