If you're sure of your numbers all you need is the final concentrations.
pH = pKa + log (base)/(acid)
pH = 4.76 + log (OAc^-)/(HOAc) but this can't be right. A buffer will have some acetate and some acetic acid. You can't have zero HOAc.
If you truly have (HOAc) = 0, then the pH is determined by the hydrolysis of the OAc^-. With no volumes I can't calculate any of the values. If it is hydrolysis, then
OAc^- + HOH ==> HOAc + OH^-
Kb for OAc = (Kw/Ka for HOAc) = (x)(x)/5.2-x and you solver for x = (OH^-) and convert to pH.
Hi, I am trying to find the pH of a buffer I created and then added NaOH to. This is my data:
total volume of solution 34.2 mL
[NaOH] before reaction 6.0
[HOAc] before reaction .8 M
[OAc-] before reaction .4 M
[HOAc] after reaction 0 M
[OAc-] after reaction 5.2 M
So, how would I calculate the pH?
2 answers
Thank you, i figured out where I made the error.
1 answer