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Asked by
Chloe
Find using substitution:
∫ 1/[x(1+lnx)^2] dx
I'm not sure what substitution to use.
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Answered by
Damon
maybe something like
let z = ln x
dz /dx = 1/x
dx = x dz
∫ 1/[x(1+lnx)^2] dx
∫ dz/[ 1+z]^2
Answered by
Chloe
Don't worry, I've got it. I used the substitution u = 1 + lnx and got the answer
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