Asked by Cami

Solve the system below.

y=x2-2x-6
y=4x+10

A. (-2, 2)
B. (8, 42)
C. (-2, 2) (8, 42)
D. There is no real solution

Answers

Answered by Damon
do you mean
y = x^2 - 2 x - 6 ????
if so then
4 x + 10 = x^2 - 2 x - 6

x^2 - 6 x - 16 = 0

(x-8)(x+2) = 0
x = +8 or x = -2
C is looking good but check it

if x = -2 does y = +2 work?
yes
if x = +8 does 42 work?
looks good so C
Answered by T^T
thanks Damon:)
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