Asked by Sam
Consider the following reaction.
2 CO (g) + O2 (g) −→ 2 CO2 (g)
What is most likely true about the entropy change for this reaction?
Delta Srxn < 0 or Delta Srxn > 0.
Why is it Delta Srxn < 0 ?
2 CO (g) + O2 (g) −→ 2 CO2 (g)
What is most likely true about the entropy change for this reaction?
Delta Srxn < 0 or Delta Srxn > 0.
Why is it Delta Srxn < 0 ?
Answers
Answered by
bobpursley
You have increased order, making three volumes two. Entropy decreases
Answered by
DrBob222
On the left you have 3 mols of gas. ON the right you have only 2 mols gas. There is more randomness (more random possibilities) in 3 mols than 2 mols.
Answered by
anon
thank you
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