Asked by Thalita
Suppose that y varies inversely as the square of x, and that y = 9 when x = 19. What is y when x = 17? (Round off your answer to 2 decimal places.)
Answers
Answered by
Steve
y = k/x^2
That is, x^2y = k is constant.
So, you want y such that
19^2 * 9 = 17^2 * y
That is, x^2y = k is constant.
So, you want y such that
19^2 * 9 = 17^2 * y
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.