Question

x+y+√z=148
x+√y+z=82
√x+y+z=98
find x,y,z given that x,y,z are all
positive integers.


Please i need the solution
#thanks

Answer 1

To me, the actual solution is less important than the method of getting that solution.
We should assume that all values would be whole numbers. More than that, all numbers would have to be perfect squares or else we would have decimals

suppose we subtract the second from the third:
√x - x + y - √y = 16
y-x + √x-√y = 16

does that give you any ideas?

Answer 2

So, there is no solution?