Solve the system.

Question

3x^2+4x-y=8
y+3=2x^2+4x

Answer 1

organize things a bit better

y = 3x^2+4x-8
y = 2x^2+4x-3

so,

3x^2+4x-8 = 2x^2+4x-3
x^2-5 = 0
x = ±√5

now use that to find y.