A 1.27 kg hoop with a radius of 10.0 cm rolls without slipping and has a linear speed of 1.32 m/s.

Find the rotational kinetic energy.

Find the total kinetic energy of the hoop.

1 answer

First, you need the moment of interia for a hoop. Look it up.

rotationalKE=1/2 I w^2=1/2 I (v/r)^2

total KE=rotationalKE+1/2 m v^2