Asked by DeYuNgVaL
a woman is 4 times as old as the son. in 5 years time she will be 3 times as old as the son. how old is the woman?....need an answer now
Answers
Answered by
Reiny
age of son ---- x
age of woman --- 4x
5 years from now:
son : x+5
woman : 4x+5
4x+5 = 3(x+5)
solve for x
age of woman --- 4x
5 years from now:
son : x+5
woman : 4x+5
4x+5 = 3(x+5)
solve for x
Answered by
ibrahim ganiat
10
Answered by
Anonymous
What is the answer
Answered by
David
Age of son = unknown, use = x
Age of woman = 4×
5 yrs time = 3× as old as son.
Thus 8 × 4 = 32yrs old
Age of woman = 4×
5 yrs time = 3× as old as son.
Thus 8 × 4 = 32yrs old
Answered by
Anonymous
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Answered by
Atilola
Thanks Reiny, you almost got the answere, since x=10 and the woman is four times. The answere is =40
Answered by
Glory
I will like to have some tests questions to help me
Answered by
Henry
What question
Answered by
Henry
X=10
Answered by
Niffy
Her son= x
Woman= 4x
Five years time
Her son=x+5
Woman = 4x+5
4x+5=3(x+5)
4x+5=3x+15
4x_3x=15_5
X=10 years ago
Woman= 4x
Five years time
Her son=x+5
Woman = 4x+5
4x+5=3(x+5)
4x+5=3x+15
4x_3x=15_5
X=10 years ago
Answered by
Anonymous
I no no 🙄
Answered by
Okafor Victoria
4x+5=3(x+5)
4x+5=3x+15
Collect like terms
4x-3x=15-5
Therefore, x=10
4x+5=3x+15
Collect like terms
4x-3x=15-5
Therefore, x=10
Answered by
Okafor Victoria
1) x+7y
2)x=5
3) (x+2)²
5) 3/8
2)x=5
3) (x+2)²
5) 3/8
Answered by
Okpala chisom
Son=x
Woman=4x
In 5yrs Time woman=4x+5
Son in 5yrs=x+5
4x+5=3(x+5)
4x+5=3x+15
4x-3x=15-5
X=10
Woman=4x
In 5yrs Time woman=4x+5
Son in 5yrs=x+5
4x+5=3(x+5)
4x+5=3x+15
4x-3x=15-5
X=10
Answered by
Bot
Here are some test questions for you:
1. Simplify: 4x + 2y - 3x + 5y
2. Solve for x: 3x + 6 = 21
3. Factorize: x² + 4x + 4
4. Find the distance between (-3, 4) and (5, -2)
5. Evaluate: (1/2)^3 - (1/2)^2 + (1/2)^1
Let me know if you need any help with these questions.
1. Simplify: 4x + 2y - 3x + 5y
2. Solve for x: 3x + 6 = 21
3. Factorize: x² + 4x + 4
4. Find the distance between (-3, 4) and (5, -2)
5. Evaluate: (1/2)^3 - (1/2)^2 + (1/2)^1
Let me know if you need any help with these questions.
Answered by
Bot
Good job! However, for question 4, the distance formula is:
d = √[(x2 - x1)^2 + (y2 - y1)^2]
Using the given points (-3, 4) and (5, -2), we can plug the values into the formula to get:
d = √[(5 - (-3))^2 + (-2 - 4)^2]
d = √[8^2 + (-6)^2]
d = √[64 + 36]
d = √100
d = 10
Therefore, the distance between the two points is 10 units.
d = √[(x2 - x1)^2 + (y2 - y1)^2]
Using the given points (-3, 4) and (5, -2), we can plug the values into the formula to get:
d = √[(5 - (-3))^2 + (-2 - 4)^2]
d = √[8^2 + (-6)^2]
d = √[64 + 36]
d = √100
d = 10
Therefore, the distance between the two points is 10 units.
Answered by
Bot
Great, that's correct! You've solved the problem correctly.
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