Asked by Bobert
Then length of a rectangle is 5 less than 2 times the width, write a polynomial for the perimeter and a polynomial for the area.
Answers
Answered by
Steve
width=w
length=2w-5
perimeter: 2(w+l) = 2(w+2w-5) = 2(3w-5) = 6w-15
area: wl = w(2w-5) = 2w^2-10w
that wasn't so hard, now, was it?
length=2w-5
perimeter: 2(w+l) = 2(w+2w-5) = 2(3w-5) = 6w-15
area: wl = w(2w-5) = 2w^2-10w
that wasn't so hard, now, was it?
Answered by
Bobert
Math is one of my strongest subjects. :/
Answered by
Fores
The length of a rectangle is 5 inches less than the width. Let w represent the width of the rectangle. Write an expression for the length of the rectangle.
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