Asked by junaid
0.717g of potassium dihydrogen phosphate in 500ml concentration in ppm
Answers
Answered by
DrBob222
0.717 g KH2PO4 in 500 mL to ppm.
You want to convert to mg/L.
717 mg/500 mL = 1434 mg/L = 1434 ppm.
You want to convert to mg/L.
717 mg/500 mL = 1434 mg/L = 1434 ppm.
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