Asked by Lucie
How much sweat (in mL) would you have to evaporate per hour to remove the same amount of heat a 120 W light bulb produces? (1W=1J/s.)
Answers
Answered by
DrBob222
120 W = 120 J/s. For 1 hour that is
120 J/s x 60 s/hr = 7200 J.
7200 = mass H2O x delta H vaporization.
Substitute and solve for mass H2O (sweat)
120 J/s x 60 s/hr = 7200 J.
7200 = mass H2O x delta H vaporization.
Substitute and solve for mass H2O (sweat)
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