As^5.V(s)+Bs^4.V(s)+Cs^3.V(s)+Ds^2.V(s)+Es^1V(s)+F.V(s)=1, where V(s) is the transformed transient output voltage. Rearranging the 5th order transient polynomial equation above we have: V(s) = 1 / H(s) where H(s) is a polynomial is a polynomial in s to be determine. The values of the above constants: A=8,D=30,E=-33,F=9. Find an equation for H(s)in terms of A,B,C,D,E and F.

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