Asked by Diane
The length of a rectangle is 2 cm more than the width. If the area is 5 cm^2, find the dimensions
Answers
Answered by
Damon
w(w+2) = 5
w^2 + 2 w - 5 = 0
(
w = [ -2 +/- sqrt (4 + 20) ]/2
w = -1 +/- .5 sqrt 24
have to use the + sign
w = 1.45
L = 3.45
w^2 + 2 w - 5 = 0
(
w = [ -2 +/- sqrt (4 + 20) ]/2
w = -1 +/- .5 sqrt 24
have to use the + sign
w = 1.45
L = 3.45
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