Question

|x+1|-|x|+3|x-1|-2|x-2|=x+2
don,t have any ideal at all
show working plz

Answer 1

you have several values, each of which has two cases.

|x+1| = x+1 if (x+1) >= 0
|x+1| = -(x+1) if (x+1) < 0

So, you need to set up the inequalities and check both values for each || quantity.

As a help, see the graphs at

http://www.wolframalpha.com/input/?i=|x%2B1|-|x|%2B3|x-1|-2|x-2|%3Dx%2B2