Asked by Jane
Find p such that px^2-12x+4=0 has only one solution.
Thank you!!!
Thank you!!!
Answers
Answered by
Bosnian
In quadratic equation:
a x ^ 2 + b x + c
value D = b ^ 2 - 4ac is called the discriminant.
When Discriminant is zero we get just one real solution.
p x ^ 2 - 12 x + 4 = 0
In this case :
a = p , b = - 12 , c = 4
D = b ^ 2 - 4 a c =
( - 12 ) ^ 2 - 4 * p * 4 =
144 - 16 p = 0 Add 16 p to both sides
144 - 16 p + 16 p = 0 + 16 p
144 = 16 p Divide both sides by 16
144 / 16 = p
9 = p
p = 9
p x ^ 2 - 12 x + 4 = 0
become:
9 x ^ 2 - 12 x + 4 = 0
By the way the solution is x = 2 / 3
a x ^ 2 + b x + c
value D = b ^ 2 - 4ac is called the discriminant.
When Discriminant is zero we get just one real solution.
p x ^ 2 - 12 x + 4 = 0
In this case :
a = p , b = - 12 , c = 4
D = b ^ 2 - 4 a c =
( - 12 ) ^ 2 - 4 * p * 4 =
144 - 16 p = 0 Add 16 p to both sides
144 - 16 p + 16 p = 0 + 16 p
144 = 16 p Divide both sides by 16
144 / 16 = p
9 = p
p = 9
p x ^ 2 - 12 x + 4 = 0
become:
9 x ^ 2 - 12 x + 4 = 0
By the way the solution is x = 2 / 3
Answered by
aaaaaaaa
the answer 9
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.