Asked by Bob
One alloy is 2 parts iron to 3 parts silver and another alloy is 7 parts iron to 3 parts silver. How much of each should be combined to produce a 30 pound alloy that is 1 part iron to 1 part silver?Please show me how to do this
Answers
Answered by
Steve
The 1st alloy (x) is 2/5 iron and the 2nd alloy (30-x) is 7/10 iron. So, you want to mix 'em up so that
(2/5)x + (7/10)(30-x) = (1/2)(30)
x = 20
Check:
20 oz of Alloy 1 contains 8 oz iron
10 oz of Alloy 2 contains 7 oz iron.
Total is 15 oz in 30 oz of the mix, or a ratio of 1:1.
(2/5)x + (7/10)(30-x) = (1/2)(30)
x = 20
Check:
20 oz of Alloy 1 contains 8 oz iron
10 oz of Alloy 2 contains 7 oz iron.
Total is 15 oz in 30 oz of the mix, or a ratio of 1:1.
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