Asked by Aimee
A car of mass 720 kg travels round a horizontal, semicircular racetrack of radius 200 m, at a constant speed of 48 km/h. What is the sideways component of the force exerted by the track on the car’s tyres?
Answers
Answered by
Damon
F = m v^2/r
where
m = 720
v = 48000/3600 = 13.33 m/s
r = 200
where
m = 720
v = 48000/3600 = 13.33 m/s
r = 200
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