Asked by rs aggarwal class 8 math si
in a fraction twince the numerator is 2 more than the denominator . if 3 is added to the numerator and to the denominator , the new fraction is 2/3 . find the original fraction.
Answers
Answered by
Damon
n / (2n -2)
(n + 3)/(2n+1) = 2/3
3(n+3) = 2 (2n+1)
3 n + 9 = 4n + 2
n = 7
so
n/(2n-2) = 7/12
(n + 3)/(2n+1) = 2/3
3(n+3) = 2 (2n+1)
3 n + 9 = 4n + 2
n = 7
so
n/(2n-2) = 7/12
Answered by
shruti singh
Let the denominator be x.
Numerator will= x+2
If 3 is added,
Numerator will be x+2+3 = x +5
Denominator will be x+3
Now,
X+5/ x+3 = 2/3
By cross multiply,
X+5 × 3 =3x + 15,
X+3×2=2x + 6,
Now,
3x+15=2x+6
3x-2x=6-15
X= -9
Numerator=-9 and denominator=-9×2= -18
Numerator will= x+2
If 3 is added,
Numerator will be x+2+3 = x +5
Denominator will be x+3
Now,
X+5/ x+3 = 2/3
By cross multiply,
X+5 × 3 =3x + 15,
X+3×2=2x + 6,
Now,
3x+15=2x+6
3x-2x=6-15
X= -9
Numerator=-9 and denominator=-9×2= -18
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