Asked by rachel
the length of a rectangle is 6 cm more than its width. if 3 cm are taken from the length and added to the width, the figure becomes a square with an area of 64sq cm. what are the dimensions of the original figure.
Answers
Answered by
Henry
Width = W cm.
Length = W+6 cm.
((W+6)-3)(W+3) = 64 cm^2.
(W+3)(W+3) = 64, W^2+6W+9 = 64, W^2+6W-55 = 0, -55 = -5*11, -5+11 = 6 = B, (W-5)(W+11) = 0,
W-5 = 0, W = 5. W+11 = 0, W = -11.
Original Dimensions: W = 5 cm, L = 5+6 = 11 cm.
Length = W+6 cm.
((W+6)-3)(W+3) = 64 cm^2.
(W+3)(W+3) = 64, W^2+6W+9 = 64, W^2+6W-55 = 0, -55 = -5*11, -5+11 = 6 = B, (W-5)(W+11) = 0,
W-5 = 0, W = 5. W+11 = 0, W = -11.
Original Dimensions: W = 5 cm, L = 5+6 = 11 cm.
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