Cl2 + 2KI --> I2 + 2KCl
6.8gKCl*1molKCl/74.55gKCl*1molCL2/2MolKCl* 70gCL2/1molCl2
6.8*1*70/(74.55*2*1)
so you did it correctly.
Can you please check my answer?
Balance the following equation:
Cl2 + KI --> I2 + KCl
How many grams of Cl2 are used to form 6.8 g of KCl?
So 6.8 grams of KCl divided by 74.55g Kcl x 1molCl2 divided by 2mol KCl multiplied by 70.91 g Cl2/mol....
3.2 grams of Cl2
2 answers
thank you