This is a probability problem
5!/(3!2!) =10 different ways.
How many different sums of money are possible using at least 3 coins from a collection consisting of one penny, one nickel, one dime, on quarter and one loonie?
2 answers
This question is not as easy as it first appears.
John found the number of ways to select exactly 3 coins from the 5 given. But it said at least 3 coins
so we could have 4 or all 5
number of ways to select
= C(5,3) + C(5,4) + C(5,5)
= 10 + 5 + 1 = 16
But we have not yet considered the value of these selections. Since it asked the number of different sums of money.
I can't see any other way than
listing all 16 combinations, and finding the value of each one.
The question is, "Are there any of the choices giving the same sum ?"
btw, since a "loonie" is a Canadian coins, I assume you re talking about Canadian coins. The teacher assigning this question should know that we have not used pennies for quite some time now.
John found the number of ways to select exactly 3 coins from the 5 given. But it said at least 3 coins
so we could have 4 or all 5
number of ways to select
= C(5,3) + C(5,4) + C(5,5)
= 10 + 5 + 1 = 16
But we have not yet considered the value of these selections. Since it asked the number of different sums of money.
I can't see any other way than
listing all 16 combinations, and finding the value of each one.
The question is, "Are there any of the choices giving the same sum ?"
btw, since a "loonie" is a Canadian coins, I assume you re talking about Canadian coins. The teacher assigning this question should know that we have not used pennies for quite some time now.